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WIP: A fisrst V0 approach - no .mat file support

master
Christos Choutouridis před 1 týdnem
rodič
revize
7c88260900
3 změnil soubory, kde provedl 103 přidání a 11 odebrání
  1. +2
    -2
      homework_1/Makefile
  2. +1
    -1
      homework_1/report/homework_1_report.tex
  3. +100
    -8
      homework_1/src/main.cpp

+ 2
- 2
homework_1/Makefile Zobrazit soubor

@@ -76,7 +76,7 @@ CSIZE := size
CFLAGS := $(DEB_CFLAGS)
CXXFLAGS := $(DEB_CXXFLAGS)
CXX := g++
CC := gcc

#
# =========== Main body and Patterns ===========
@@ -264,7 +264,7 @@ csal_v1: $(BUILD_DIR)/$(TARGET)
# examples:
#
# make IMAGE=hpcimage EXEC=knnsearch_v1 run
# make IMAGE=hpcimage EXEC=knnsearch_cilkv1 run
# make IMAGE=hpcimage EXEC=knnsearch_v1 run
#
run: DOCKER := $(DOCKER_CMD)
run:


+ 1
- 1
homework_1/report/homework_1_report.tex Zobrazit soubor

@@ -1,5 +1,5 @@
%
% Network programming Lab sum report
% PDS homework_1 report
%
% authors:
% Χρήστος Χουτουρίδης ΑΕΜ 8997


+ 100
- 8
homework_1/src/main.cpp Zobrazit soubor

@@ -1,15 +1,107 @@
#include <iostream>
#include <cblas.h>
#include <cmath>
#include <vector>
#include <algorithm>
#include <queue>

/*!
* Function to compute squared Euclidean distances
*
* \fn void pdist2(const double*, const double*, double*, int, int, int)
* \param X m x d matrix
* \param Y n x d matrix
* \param D2 m x n matrix to store distances
* \param m number of rows in X
* \param n number of rows in Y
* \param d number of columns in both X and Y
*/
void pdist2(const double* X, const double* Y, double* D2, int m, int n, int d){
// Compute the squared norms of each row in X and Y
std::vector<double> X_norms(m), Y_norms(n);
for (int i = 0; i < m; ++i) {
X_norms[i] = cblas_ddot(d, X + i * d, 1, X + i * d, 1);
}
for (int j = 0; j < n; ++j) {
Y_norms[j] = cblas_ddot(d, Y + j * d, 1, Y + j * d, 1);
}

// Compute -2 * X * Y'
cblas_dgemm(CblasRowMajor, CblasNoTrans, CblasTrans, m, n, d, -2.0, X, d, Y, d, 0.0, D2, n);

// Step 3: Add the squared norms to each entry in D2
for (int i = 0; i < m; ++i) {
for (int j = 0; j < n; ++j) {
D2[i * n + j] += X_norms[i] + Y_norms[j];
D2[i * n + j] = std::max(D2[i * n + j], 0.0); // Ensure non-negative
D2[i * n + j] = std::sqrt(D2[i * n + j]); // Take the square root of each
}
}
}

void quickselect(std::vector<std::pair<double, int>>& vec, int k) {
std::nth_element(
vec.begin(),
vec.begin() + k,
vec.end(),
[](const std::pair<double, int>& a, const std::pair<double, int>& b) {
return a.first < b.first;
});
vec.resize(k); // Keep only the k smallest elements
}

// K-nearest neighbor search function
void knnsearch(const double* C, const double* Q, int m, int n, int d, int k,
std::vector<std::vector<int>>& idx, std::vector<std::vector<double>>& dst) {
std::vector<double> D(m * n);
pdist2(C, Q, D.data(), m, n, d);

idx.resize(n, std::vector<int>(k));
dst.resize(n, std::vector<double>(k));

for (int j = 0; j < n; ++j) {
// Create a vector of pairs (distance, index) for the j-th query
std::vector<std::pair<double, int>> dst_idx(m);
for (int i = 0; i < m; ++i) {
dst_idx[i] = {D[i * n + j], i};
}

// Find the k smallest distances using quickSelectKSmallest
quickselect(dst_idx, k);

// Sort the k smallest results by distance for consistency
std::sort(dst_idx.begin(), dst_idx.end());

// Store the indices and distances
for (int i = 0; i < k; ++i) {
idx[j][i] = dst_idx[i].second;
dst[j][i] = dst_idx[i].first;
}
}
}

int main(){

double A[6] = {1.0,2.0,1.0,-3.0,4.0,-1.0};
double B[6] = {1.0,2.0,1.0,-3.0,4.0,-1.0};
double C[9] = {.5,.5,.5,.5,.5,.5,.5,.5,.5};
cblas_dgemm(CblasColMajor, CblasNoTrans, CblasTrans,3,3,2,1,A, 3, B, 3,2,C,3);
int m = 5; // Number of points in C (corpus)
int n = 3; // Number of points in Q (query)
int d = 2; // Dimensions
int k = 2; // Number of nearest neighbors to find

double C[] = {1.0, 2.0, 3.0, 4.0, 5.0, 6.0, 7.0, 8.0, 9.0, 10.0}; // m x d matrix
double Q[] = {1.5, 2.5, 3.5, 4.5, 5.5, 6.5}; // n x d matrix

std::vector<std::vector<int>> idx;
std::vector<std::vector<double>> dst;

knnsearch(C, Q, m, n, d, k, idx, dst);

// Print results
for (int i = 0; i < n; ++i) {
std::cout << "Query point " << i << ":\n";
for (int j = 0; j < k; ++j) {
std::cout << " Neighbor " << j <<": Index = " << idx[i][j] <<", Distance = " << dst[i][j] << '\n';
}
}

for (int i=0 ; i<9 ; ++i)
std::cout << C[i] << ' ';
std::cout << '\n';
return 0;
return 0;
}

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